Belfort says he would ‘beat the crap’ out of Jake Paul and Logan Paul on the same night

Vitor Belfort makes an appearance at Mayweather Boxing Gym in Las Vegas, Nevada to support for his friend Badou Jack. | Photo by Louis Grasse/PxImages/Icon Sportswire via Getty Images

“I’ll beat the crap out of these two brothers like that. Like that. They know that. They don’t want to do it. They’re afraid”.

UFC legend Vitor Belfort is the latest MMA fighter to call out YouTube brothers Jake Paul and Logan Paul, with ‘The Phenom’ claiming that he would KO both fighters in back-to-back fights on the same night.

Belfort called out both Jake and Logan ahead of his upcoming boxing match against Oscar De La Hoya on Sept. 11, accusing the social media celebrities of being afraid of him.

“I’m telling you, you put these two brothers with me, I will fight both guys in the same night,” Belfort told MMA Fighting’s Damon Martin in a recent interview. “You come, you get tired, comes the other brother next round, I’ll beat the crap out of these two brothers like that. Like that. They know that. They don’t want to do it. They’re afraid.

“The Triller guys said ‘Vitor, when we brought your name up, they are shaken up oh no not him!’ and they’re choosing these guys, the wrestlers.”

Jake Paul is undefeated at 3-0 while older brother Logan, who recently fought Floyd Mayweather Jr. in an eight-round exhibition, is 0-1.

Jake will return to the boxing ring on Aug. 28 to take on Tyron Woodley in what many believe will be his toughest test to date but Belfort believes the Disney actor is picking cherry picking easy matchups.

“A lot of guys avoid me, especially these YouTuber brothers [Logan and Jake Paul], they’ve been avoiding me for years and they’re looking for easy fights, easy money,” Belfort said. “They’re lucky cause I’ll rip their head off. This guy came and accepted and I said let’s go.”

Belfort, 44, will take on multiple-time boxing world champion Oscar De La Hoya in an exhibition match on Sept. 11 at a TBA venue in Las Vegas, Nevada.

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